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2 years ago

the eccentricity of the Moon's orbit is low, medium, or high with respect to most of the planets' orbits around the sun?

Physics

1 answer:

12345 [234]2 years ago

4 0

person sorry answering for points

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The theory of continental drift is supported by all of the following EXCEPT

True [87]

Except for climate which has changes over the eons.

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3 years ago

A student pushes against a wall with a force of 30N. The wall does not move. What amount of force does the wall exert on the stu

True [87]

Answer:

Explanation:

they both have to be the same for both to not move

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1 year ago

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In one experiment, the students allow the block to oscillate after stretching the spring a distance A. If the potential energy s

atroni [7]

Answer:

K = m g (A - A2)

Explanation:

In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

Em = K + U₂

K = Em –U₂

We substitute

K = m g A - m gA2

K = m g (A - A2)

3 0

2 years ago

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The acceleration due to gravity on the Moon's surface is

Molodets [167]

Answer:

50 lb

Explanation:

Given,

The weight of astronaut's life support backpack on Earth (w) = 300 lb

Acceleration due to gravity on Earth (g) = 9.8 m/s²

Acceleration due to gravity on Moon = g'

$g'=\frac{g}{6}$

We know that weight of an object on Earth is,

$w = m\times g$

$m = \frac{w}{g}$

Similarly, weight on Moon will be

$w' = m\times g'$

$w' = \frac{w}{g}\times\frac{g}{6}$

$w' = \frac{300}{6}$

$w' = 50$

Thus the astronaut's life support backpack will weigh 50 lb on Moon.

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2 years ago

What are the foci of the ellipse given by the equation 100x^2 + 64y^2 = 6 400?

NikAS [45]

The equation of our ellipse is:

$100 x^2 + 64 y^2 = 6400$ (1)

First, let's reduce the equation of the ellipse to the standard form:

$\frac{x^2}{a^2}+ \frac{y^2}{b^2}=1$

To do that, we should divide both terms of equation (1) by 6400, and we get:

$\frac{x^2}{64}+ \frac{y^2}{100}=1$

This is a vertical ellipse (because $b^2 \ \textgreater \ a^2$ ) centered in the origin, and so the distance of its foci from the origin (on the y axis) is given by

$c= \sqrt{b^2-a^2}= \sqrt{(100)-(64)}=6$

Therefore, the position of the two foci is (0,6) and (0,-6)

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2 years ago