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3 years ago

A 250 l container with 2.86 kg of propane gas (c3h8) is at a temperature of 30.2 ºc. what is the pressure (atm) of the gas?

1 answer:

max2010maxim [7]3 years ago

5 0

Data Given:
Pressure = P = ?

Volume = V = 250 L

Temperature = T = 30.2 °C + 273 = 303.2 K

Mass = m = 2.86 Kg = 2860 g

Moles = n = 2860 g / 44.1 g.mol⁻¹ = 64.85 moles

Solution:
Let suppose the gas is acting Ideally, Then According to Ideal Gas Equation.

P V = n R T
Solving for P,
P = n R T / V

Putting Values,

P = (64.85 mol × 0.0821 atm.L.mol⁻¹.K⁻¹ × 303.2 K) ÷ 250 L

P = 6.45 atm

You might be interested in

- How many moles of H2O are required to react to form 2.5 grams of CH ?

abruzzese [7]

Answer:

0.312 moles of H2O

Explanation:

no. of moles of ch4= mass ÷ molar mass

=2.5 ÷ 16.04

=0.156 moles of ch4

According to balanced chemical equation

CH4 : H2O

1 mole : 2 moles

0.156 moles : x moles

by cross multiplication

x= (0.156x2) ÷ 1

= 0.312 moles of H2O

7 0

2 years ago

The _________ indicates that 70% of the Sun's radiation is contained on Earth and 30% is reflected back into space.

vichka [17]

i think it would be Earth's albedo hope this helps

4 0

2 years ago

Read 2 more answers

At a certain temperature the vapor pressure of pure heptane C7H16 is measured to be 454.mmHg. Suppose a solution is prepared by

OlgaM077 [116]

Answer:

Mass of heptane = 102g

Vapor pressure of heptane = 454mmHg

Molar mass of heptane = 100.21

No of mole of heptane = mass/molar mass = 102/100.21

No of mole of heptane = 1.0179

Therefore the partial pressure of heptane = no of mole heptane *Vapor pressure of heptane

Partial pressure of heptane = 1.0179*454mmHg

Partial pressure of heptane = 462.1096 = 462mmHg

the partial pressure of heptane vapor above this solution = 462mmHg

5 0

2 years ago

A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.50 grams of aluminum foil in a solut

Irina-Kira [14]

Answer:

Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.

Explanation:

It is a stichiometry problem.

We should write the balance equation of the mentioned chemical reaction:

2Al + 3CuCl₂ → 3Cu + 2AlCl₃.

It is clear that 2.0 moles of Al foil reacts with 3.0 moles of CuCl₂ to produce 3.0 moles of Cu metal and 2.0 moles of AlCl₃.

Also, we need to calculate the number of moles of the reported masses of Al foil (0.50 g) and CuCl₂ (0.75 g) using the relation:

n = mass / molar mass

The no. of moles of Al foil = mass / atomic mass = (0.50 g) / (26.98 g/mol) = 0.0185 mol.

The no. of moles of CuCl₂ = mass / molar mass = (0.75 g) / (134.45 g/mol) = 5.578 x 10⁻³ mol.

From the stichiometry Al foil reacts with CuCl₂ with a ratio of 2:3.

∴ 3.85 x 10⁻³ mol of Al foil reacts completely with 5.578 x 10⁻³ mol of CuCl₂ with (2:3) ratio and CuCl₂ is the limiting reactant while Al foil is in excess.

From the stichiometry 3.0 moles of CuCl₂ will produce the same no. of moles of copper metal (3.0 moles).
So, this reaction will produce 5.578 x 10⁻³ mol of copper metal.
Finally, we can calculate the mass of copper produced using:

mass of Cu = no. of moles x Atomic mass of Cu = (5.578 x 10⁻³ mol)(63.546 g/mol) = 0.354459 g ≅ 0.36 g.

So, the answer is:

Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.

5 0

3 years ago

Identify which of the following two reactions you would expect to occur more rapidly: (1) addition of HBr to 2-methyl-2-pentene

arlik [135]

Answer:

(1) addition of HBr to 2-methyl-2-pentene

Explanation:

In this case, we will have the formation of a carbocation for each molecule. For molecule 1 we will have a tertiary carbocation and for molecule 2 we will have a secondary carbocation.

Therefore the most stable carbocation is the one produced by the 2-methyl-2-pentene. So, this molecule would react faster than 4-methyl-1-pentene. (See figure)

3 0

2 years ago