Question

29.2 kJ of heat is required to convert an 50.0 g sample of

Answer 1

Answer:

The heat of  vaporization of acetaldehyde is 25.72 kJ/mol.

Explanation:

Mass of acetaldehyde = 50.0 g

Molar mass of acetaldehyde = 44.05 g/mol

Moles of acetaldehyde = $\frac{50.0 g}{44.05 g/mol}=1.1351 mol$

Amount of energy required to vaporize 50.0 grams of acetaldehyde = Q

Q = 29.2 kJ

The heat of  vaporization of acetaldehyde :

$\Delta H_{vap}=\frac{Q}{n}=\frac{29.2 kJ}{1.1351 mol}=25.72 kJ/mol$