(a^2 + 3a - 18 / a^2 - 5a +6)(5a - 10 / a^2 -36)

1 answer:

8 0

$\frac{a^{2}+3a-18}{a^2-5a+6} * \frac{5a-10}{a^{2}-36} = \frac{(a+6)(a-3)}{(a-2)(a-3)} * \frac{5(a-2)}{(a+6)(a-6)} = \frac{5}{a-6} ,

where a \neq 2, a \neq 3, a \neq +6,a \neq -6$

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Each point has been reflected over the x-axis or y-axis.

Amanda [17]

The reflection is

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<h3>What is reflection over axis?</h3>

A reflection of a point, a line, or a figure in the X axis involved reflecting the image over the x axis to create a mirror image. In this case, the x axis would be called the axis of reflection.

For reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same.

and, for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y value the same.

So, by considering the above value rules the reflection of the given points as follows over respective axis.

E(7, 1) ⇒ (7, -1)

Here, the reflection is over x-axis because the y value is changing

F(-3, 5) ⇒ (-3, -5)

Here, the reflection is over x-axis because the y value is changing

G(6, -2) ⇒ (-6, -2)

Here, the reflection is over y-axis because the x value is changing.

Learn more about this concept here:

brainly.com/question/15175017

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