since the perimeter of two semicircles adds up to that of one circle, the perimeter of the track would be the perimeter of the circle + the length of the rectangle.
we can find the perimeter of the circle using the formula of π × diameter, which would be:
π × diameter
= 3.14 × 74
= 232.36
now, we can add this to the given length of the rectangle:
232.36 + 1000 + 1000 = 2232.36
thus, the perimeter of the track is <u>2232.36m</u>.
easy 230-80 which is 150 so imagine a triangle with base 150 and hight 130-60=70 so times for area 150×70÷2 because it's triangle which is <em>5</em><em>2</em><em>5</em><em>0</em> so plus that with 130x80 for rectangle which is 10400 and add so it's 15650
800-20 is 780. A third of 780 is 780(1/3) = 260. 780 - 260 = 520. 25% of $520 is 0.25(520) = 130. 520 - 130 = 390. One sixth of 390 is 390(1/6) = 65. 390 - 65 = 325. So, Bob kept $325 for himself.
