A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.

Mathematics

2 answers:

ivanzaharov [21]2 years ago

7 0

Answer:

47 is the right answer! Have an cool day!

Dahasolnce [82]2 years ago

5 0

By rotating the picture counterclockwise, it is clear that it is a square.

Calculate the length of one side of the picture by using coordinates (1, -3) and (2,1).
a = [(2-1)^2 + (1+3)^2]^0.5 = (1 + 8)^0.5 = 3
The area of the picture is 3^2 = 9.

Calculate the area of the red paper.
Area = 8*8 = 64

Calculate the area of the red paper after the photograph has been cut.
Area = 64 - 9 = 55

Answer: 55

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What is the area of this parallelogram? PLEASE HELP

zimovet [89]

Answer:

Step-by-step explanation:

the area of a parallelogram is the length of one of the sides multiplied with the length of the height on this side.

so, in this case it is

4×5 = 20 cm²

5 0

1 year ago

Implicit differentiation of 1/x +1/y=5 y(4)= 4/19<br> y'(4)=?

Aneli [31]

$\frac{1}{x} +\frac{1}{y} = 5\\\\x^{-1}+y^{-1}=5\\$

Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

$-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}$

Now that we have dy/dx, we can plug in the x, which is 4, and the y, which is 4/19. We know these values of x and y because your question stated y(4) = 4/19.

$\frac{dy}{dx}=-5(\frac{4}{19})^2-\frac{(\frac{4}{19})^2}{(4)^2}\\\\\frac{dy}{dx}=-5(\frac{16}{361})-\frac{(\frac{16}{361})}{16}\\\\\frac{dy}{dx}=\frac{-80}{361}-\frac{1}{361}\\\\\frac{dy}{dx}=\frac{-81}{361}$

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3 years ago

HELP!!!

Bad White [126]

I hope this helps you

-15+6= -9

-9+6= -3

-3+6=3

add 6

3 0

2 years ago

Read 2 more answers

Find the slope of a line that has points (-2,6) and (4,-1)

Nadya [2.5K]

-7/6 is the answer hope it helped

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