Hi. The slope of the line is undefined, because it's vertical.
Step-by-step explanation:
the max. value is when the smaller set (A) is completely contained in the larger set (B).
then n(A n B) is n(A) = 50.
the set intersection between A and B cannot get bigger than that. or A gets bigger ...
after all, the intersection means it is a set of all elements that exist in BOTH sets.
but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.
the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.
in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.
1. b
2. e
3. a
4. c
5. d
6. f
7. g
8. h
hope this helps there is really no way of explaining you would have to study you theorems
Answer:
The 95% Confidence Interval for the difference between the two population mean completion times =
(0.081, 1.919)
Step-by-step explanation:
Confidence Interval for difference between two means =
μ1 -μ2 ± z × √ σ²1/n1 + σ²2/n2
Where
μ1 = mean 1 = 12 mins
σ1 = Standard deviation 1 = 2 mins
n1 = 100
μ2= mean 2 = 11 mins
σ2 = Standard deviation 2 = 3 mins
n1 = 50
z score for 95% confidence interval = 1.96
μ1 -μ2 ± z × √ σ²1/n1 + σ²2/n2
= 12 - 11 ± 1.96 × √2²/100 + 3²/50
= 1 ± 1.96 × √4/100 + 9/50
= 1 ± 1.96 × √0.04 + 0.18
= 1 ± 1.96 × √0.22
= 1 ± 1.96 × 0.469041576
= 1 ± 0.9193214889
Confidence Interval
= 1 - 0.9193214889
= 0.0806785111
≈ 0.081
1 + 0.9193214889
= 1.9193214889
≈ 1.919
Therefore, the 95% Confidence Interval for the difference between the two population mean completion times =
(0.081, 1.919)
Hey there! I'm happy to help!
When rotating a point 90 degrees clockwise about the origin, our original point (x,y) becomes (-y,x), because it is now at a negative y-value.
We see that our point P is at (1,2). We can use this rotation formula to find the coordinates of P' (the new spot where P is)/
(x,y)⇒(-y,x)
(1,2)⇒(-2,1)
Therefore, the coordinates of the point P' are (-2,1).
Have a wonderful day! :D