<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
I do believe that the LCD of those would be 3
Answer:
-When (2×-5) intersects at ×-axis the value of × will be zero.
=>F(×)=× 0=2×-5
hence,
0,=2×-5
5=2×
=>×=5/2
Step-by-step explanation:
hpe it hlps
Let's use the furthest left point on the triangle to figure out the translation.
Blue triangle = (-5,1)
Black triangle = (-3,-1)
To get from -5 to -3 we moved the triangle 2 units to the right, which means that we added 2.
To get from 1 to -1, we moved the triangle 2 units down, which means we subtracted 2.
Rule: {2, -2}
Hope this helps!