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2 years ago

15. The mass of a sample of iron is 114 g, and the density of iron is 7.86 g/cm3. What is the volume of this iron sample?

Chemistry

1 answer:

anyanavicka [17]2 years ago

5 0

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density}$

From the question

mass of iron = 114 g

density = 7.86 g/cm³

The volume is

$volume = \frac{114}{7.86} \\ = 14.50381679$

We have the final answer as

Hope this helps you

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Answer:

33300J

Explanation:

Given parameters:

Mass of ice = 100g

Unknown:

Amount of energy = ?

Solution:

This is a phase change process from solid to liquid. In this case, the latent heat of melting of ice is 3.33 x 10⁵ J/kg.

So;

H = mL

m is the mass

L is the latent heat of melting ice

Now, insert the parameters and solve;

H = mL

mass from gram to kilogram;

100g gives 0.1kg

H = 0.1 x 3.33 x 10⁵ = 33300J

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Which property of water explains why seawater contains over 20 different elements? select one:

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A chemist has 3.55x1022 molecules of nitrogen monoxide. How

Alina [70]

Answer:

<h2>0.059 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

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L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

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We have the final answer as

<h3>0.059 moles</h3>

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2 years ago

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A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif

slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

$Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})$

where,

Q = heat absorbed by metal = 186.75 J

$m_1$ = Mass of metal= 19 g

$T_1$ = Initial temperature of metal = $35^oC$

$T_2$ =Final temperature of metal = $175^oC$

$c$ = specific heat of metal= ?

$186.75 J=19 g\times c\times (175^oC-35^oC)$

$c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}$

$c=0.0702J/g^oC$

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2 years ago