Answer:
∠ ABC = 81° , ∠ FEC = 90°
Step-by-step explanation:
Since AB ≅ BC then Δ ABC is isosceles.
The median BE is therefore
The angle bisector of ∠ ABC and
BE bisects AC at right angles.
Thus
∠ ABE = ∠ CBE = 40° 30' , then
∠ ABC = 2 × 40° 30' = 81°
Since BE is perpendicular to AC then
∠ FEC = 90°
Answer:
∠ 5 = 49°, ∠ 6 = 131°
Step-by-step explanation:
∠ 5 and 49° are corresponding angles and are congruent, then
∠ 5 = 49°
∠ 5 and ∠ 6 are adjacent angles and are supplementary, sum to 180° , that is
∠ 6 + ∠ 5 = 180°
∠ 6 + 49° = 180° ( subtract 49° from both sides )
∠ 6 = 131°
Answer:
Step-by-step explanation:
- sqrt(39) and square root 47
are the limits. The - square root of 39 is smaller than - 6. So the integer to use here is - 6
sqrt (47) = 6.686. Here the square root is larger than the closest integer.
The integer to use is 6
- 6 + 6 = 0
f(x)= -2x+1 {-2,0,2,4,6}
If x=-2, then -2(-2)+1 = 5
If x=0, then -2(0)+1 = 1
If x=2, then -2(2)+1 = -3
If x=4, then -2(4)+1 = -7
If x=6, then -2(6)+1 = -11
Answer:
B {5,1,-3,-7,-11}
Area of a semi circle = pi * radius^2 / 2
3.14 * 5^2 / 2
3.14 * 25 / 2
78.5 / 2
39.5
Area of a rectangle = length * width
16 * 10
160
Add both of the areas
39.5 + 160
C. 199.5
