Answer:
<u>Alternative hypothesis 1</u>: the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2</u>: the mean amperage at which the fuses burn out is < 40 amperes.
Step-by-step explanation:
Recall that the null hypothesis is the fact you want to refute and is in doubt.
So, in this specific case, <em>the null hypothesis would be that the mean amperage at which the fuses burn out is 40 amperes.
</em>
The alternative hypothesis are those that want to refute the null hypothesis, in this case there are 2:
<u>Alternative hypothesis 1:</u> the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2:</u> the mean amperage at which the fuses burn out is < 40 amperes.
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Answer:
1. about 11.18
2. about 8.66
Step-by-step explanation:
1. 5^2 + 10^2= 125
square root of 125 equals about 11.18
2. 10^2-5^2=75
square root of 75 equals about 8.66
The answer is C. 1/7, 9, 2 Hoped this helped
Feel free to ask anymore questions at branily.com
Answer:
Number of offices to be cleaned to cover the cost of equipment =15
Cost of equipment =$.315 Cost of supplies =$.4 Charge per office =$.25
Number of offices to be cleaned to cover the cost of equipment =x
Then -25x − 4x =315
21x =315
x=315
21=15
Number of offices to be cleaned to cover the cost of equipment =15