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3 years ago

Solve the equation x2+6x+8=0?

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

Answer:

28 , 28, -14

Step-by-step explanation:

x2+6x+8=0

4(2)+6(2)+8=0

8+12+8=0

28=0

x2+6x+8=0

-4(2)+6(2)+8=0

8+12+8=0

28=0

x2+6x+8=0

-8(2)+6(-1)+8=0

-16-6+8

-14=0

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Baseball's division series is a best of five game series. That is, the first team to win 3 games is the winner. Team A and team

iris [78.8K]

Answer:

1. 27.46% probability that A wins the series in 3 games.

2. There is a 28.84% probability A wins the series in 4 games.

3. There is a 20.18% probability A wins the series in 5 games.

4. There is a 76.48% probability A wins the series.

5. There is a 71.825% probability A wins the series if a "best-of-three" game series is played.

Step-by-step explanation:

For each game, there are these following probabilities:

A 65% probability team A wins.

A 35% probability team B wins.

The combination formula is important to solve this problem:

This is because for example, team A winning games 1,2 and 4 and team B winning game 3 is the same as team A winning games 1,3,4 and team B winning game 2. That is, the order is not important.

$C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

1. What the probability that A wins the series in 3 games?

This is team A winning all 3 games. For each game, there is a 65% probability that team A wins. So

$P = (0.65)^{3} = 0.2746$

There is a 27.46% probability that A wins the series in 3 games.

2. What is the probability A wins the series in 4 games?

This is the team A winning three games and the team B 1. The team B win cannot happen in the fourth game, so the number of possibilities is a combination of 3 by 2. So

$C_{3,2} = \frac{3!}{2!1!} = 3$

The probability that team A wins the series in 4 games is:

$P = 3*(0.65)^{3}*(0.35) = 0.2884$

There is a 28.84% probability A wins the series in 4 games.

3.What is the probability A wins the series in 5 games?

This is the team A winning three games and the team B 2. The team B second win cannot happen in the fifth game, so the number of possibilities is a combination of 4 by 2. So

$C_{4,2} = \frac{3!}{2!1!} = 6$

The probability that team A wins the series in 5 games is:

$P = 6*(0.65)^{3}*(0.35)^{2} = 0.2018$

There is a 20.18% probability A wins the series in 5 games.

4. What is the probability A wins the series (period)?

They can win the series in 3,4 or 5 games. So this is the sum of the answers for 1,2,3.

$P = 0.2746 + 0.2884 + 0.2018 = 0.7648$

There is a 76.48% probability A wins the series.

5. What is the probability A wins the series if a "best-of-three" game series is played?

These three following outcomes are accepted:

A - A

A - B - A

B - A - A

$P = (0.65)^{2} + 2*(0.65)^{2}*(0.35) = 0.71825$

There is a 71.825% probability A wins the series if a "best-of-three" game series is played.

3 0

2 years ago

Stephen is a good basketball player who makes 75% of free throws. He practices so often that he never feels tired even if you as

BabaBlast [244]

Answer:

100 percent

Step-by-step explanation:

If he makes 150 throws out of 200, that is 75 percent so he is guaranteed to make at least 150

8 0

2 years ago

Can someone please help me

nydimaria [60]

You answer is correct

6 0

2 years ago

You purchased a computer for your business for $800 using straight line depreciation, the amount of depreciation allowed for eac

liberstina [14]

Answer:

this is a linear function

Step-by-step explanation:

y = a + bx

in this case:

y = 800 - 114.29x

where:

y = accumulated depreciation

x = number of years

year accumulated

(x) depreciation (y)

0 0

1 114.29

2 228.58

3 342.87

4 457.16

5 571.45

6 685.74

7 800

6 0

2 years ago

The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26

hjlf

Answer:

Probability that next week's show will have between 30 and 37 million viewers is 0.2248.

Step-by-step explanation:

We are given that the distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million.

<em>Let X = number of viewers for the American Idol television show</em>

So, X ~ N( $\mu=26,\sigma^{2}=8^{2}$ )

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 26 million

$\sigma$ = standard deviation = 8 million

So, probability that next week's show will have between 30 and 37 million viewers is given by = P(30 < X < 37) = P(X < 37) - P(X $\leq$ 30)

P(X < 37) = P( $\frac{X-\mu}{\sigma}$ < $\frac{37-26}{8}$ ) = P(Z < 1.38) = 0.91621

P(X $\leq$ 30) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{30-26}{8}$ ) = P(Z $\leq$ 0.50) = 0.69146

<em>Therefore, P(30 < X < 37) = 0.91621 - 0.69146 = 0.2248</em>

Hence, probability that next week's show will have between 30 and 37 million viewers is 0.2248.

4 0

2 years ago