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2 years ago

Plz help due tomorrow

Mathematics

2 answers:

STatiana [176]2 years ago

6 0

You chose the right one

Tomtit [17]2 years ago

6 0

Answer:

option 1

Step-by-step explanation:

Combine like terms

$1 + 4.25n + \frac{3}{2}p - 3 + (-2p) + \frac{5}{4}n=1 - 3 + 4.25n +\frac{5}{4}n+\frac{3}{2}p+(-2p)\\$

$= -2 + 4.25n + 1.25n + \frac{3}{2}p-\frac{2*2}{1*2}p\\\\= - 2 + 5.5n +\frac{3}{2}p+\frac{4}{2}p\\\\= -2 + 5.5n +\frac{3-4}{2}p\\\\= - 2 + 5.5n -\frac{1}{2}p\\\\= 5.5n - \frac{1}{2}p - 2$

You might be interested in

Which are the solutions of x2 = 19x + 1?

Finger [1]

Answer:

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Step-by-step explanation:

we have

$x^2=19x+1$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2}-19x-1=0$

$a=1\\b=-19\\c=-1$

substitute in the formula

$x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}$

$x=\frac{19\pm\sqrt{365}} {2}$

$x=\frac{19+\sqrt{365}} {2}$

$x=\frac{19-\sqrt{365}} {2}$

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0

2 years ago

Read 2 more answers

50 POINTS PLS HELP!!!!

VARVARA [1.3K]

The plot of the PDF shows the distribution is symmetric. This means that the mean is the same as the median, and that the 50% of the distribution lies to other side of this mean, i.e.

$P(X\ge a)=P(X\le a)=0.50$