Answer: The mass percent of hydrogen in ascorbic acid is 4.5 %
Explanation:
In , there are 6 carbon atoms, 8 hydrogen atoms and 6 oxygen atoms.
To calculate the mass percent of element in a given compound, we use the formula:
Mass of hydrogen =
Molar Mass of ascorbic acid =
Putting values in above equation, we get:
Hence, the mass percent of of hydrogen in ascorbic acid is 4.5 %.
Answer:Vinegar Is 5% Acetic Acid And Its Molarity Is 0.833M.
Explanation:
yes
Density = 1.01 g/cm^3 or 1.01 kg/dm^3 or 1010 kg/m^3
Density = mass/volume = 1010 g/1000 cm^3 = 1.01 g/cm^3 = 1.01 kg/dm^3
= 1010 kg/m^3
Answer : The isoelectronic groups are:
Explanation :
Isoelectronic : It is defined as the compound or molecule having the same number of electrons and the same number of electronic structure.
- The element is helium. The number of electrons are 2.
- The element is beryllium. The number of electrons are 4. The number of electrons in = 4 - 2 = 2
- The element is lithium. The number of electrons are 3. The number of electrons in = 3 - 1 = 2
- The element is nitrogen. The number of electrons are 7. The number of electrons in = 7 + 3 = 10
- The element is neon. The number of electrons are 10.
- The element is sulfur. The number of electrons are 16. The number of electrons in = 16 + 2 = 18
- The element is magnesium. The number of electrons are 12. The number of electrons in = 12 - 2 = 10
- The element is titanium. The number of electrons are 22. The number of electrons in = 22 - 4 = 18
- The element is potassium. The number of electrons are 19. The number of electrons in = 19 - 1 = 18
The isoelectronic groups are:
Answer:
Percentage abundance of 121 Sb is = 57.2 %
Percentage abundance of 123 Sb is = 42.8 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 121 Sb :
% = x %
Mass = 120.9038 u
For second isotope, 123 Sb:
% = 100 - x
Mass = 122.9042 u
Given, Average Mass = 121.7601 u
Thus,
Solving for x, we get that:
x = 57.2 %
<u>Thus, percentage abundance of 121 Sb is = 57.2 %
</u>
<u>percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %</u>