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2 years ago

Help ASAP with this question.

Mathematics

1 answer:

Likurg_2 [28]2 years ago

3 0

The answer would be the top left one because when dividing, you would subtract 8 from 13. I'm pretty sure not 100% though. Sorry.

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Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

9 months ago

PLEASE HELP ILL GIVE BRAINLIEST

cestrela7 [59]

Yea I wanna say you have the right answer

8 0

2 years ago

On a math test, Jessica answered 20% questions incorrectly. She answered 16 questions correctly. How many total questions did sh

Tanzania [10]

The answer to the question is 36

8 0

2 years ago

Read 2 more answers

Point J has coordinates (–3, 4) in the coordinate plane. Point K has coordinates (3, 4). Both points will be reflected across th

kumpel [21]

The location of the image of points <em>J </em>and <em>K </em>following a reflection across the x-axis are;

J'(-3, -4), and K'(3, -4)

<h3>Which method can be used to find the image of a point following a reflection?</h3>

Coordinates of point are;

J(-3, 4), K(3, 4)

The given transformation is; A reflection across the x-axis

The representation of a reflection across the x-axis is presented as follows;

(x, y) → (x, -y)

The image of <em>J </em>and <em>K </em>following a transformation across the x-axis are therefore;

J(-3, 4) → J'(-3, -4)

K(3, 4) → K'(3, -4)

Learn more about reflection transformation on the coordinate plane here:

brainly.com/question/8242111

#SPJ1

8 0

1 year ago

The sum of three numbers is 102. The first number is 6 more than the second. The third number is 4 times the second. What are th

const2013 [10]

Answer:

1st number: 22

2nd number: 16

3rd number: 64

Step-by-step explanation:

x + y + z = 102

x = 6 + y

z = 4y

plug that in!

(6 + y) + y + (4y) = 102

get rid of the parenthesis (I added them so you could see what I was replacing) and add like terms.

6 + 6y = 102

move 6 to the other side.

6y = 96

y = 16

now that you know one number, you can solve the equations for the rest!

x = 6 + (16)

z = 4(16)

__________________________________________________________

x = 22

y = 16

z = 64

6 0

2 years ago