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2 years ago

In a class of 25 students, 18 of them brought in permission slips for a field trip.

Mathematics

1 answer:

natali 33 [55]2 years ago

3 0

Answer:

A.18/25

B.72% of them brought in their permission slips

C.0.72

D.There the exact same value and we would divide by 100 to go from percentage to decimal and multiply by 100 to go to decimal to percentage Sign.

Step-by-step explanation:

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At the beginning of my bike ride I feel good, so I can travel 20 miles per hour. Later, I get tired and travel only 12 miles per

Vesnalui [34]

Answer: $3\dfrac{1}{4}$ hours

Step-by-step explanation:

Let x be the time ( in hours ) you feel good and y be the time ( in hours ) that you get tired.

As per given , we have

x+y= 8

Since : $Distance = Speed\times Time$

So , we have

20x+12y=122

According to the given question , we have the following system of equations ,

$x+y= 8--------(1)\\\\20x+12y=122------------------(2)$

Multiply 12 on both sides of equation (1) , we get

$12x+12y=96------------(3)$

Eliminate equation (3) from (2) , we get

$8x=26\\\\\Rightarrow\ x=\dfrac{13}{4}=3\dfrac{1}{4}$

Hence, you felt $3\dfrac{1}{4}$ hours good.

3 0

2 years ago

Help much appreciated ):

sweet-ann [11.9K]

Answer

Step-by-step explanation:

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2 years ago

Suppose taxi fare from Logan Airport to downtown Boston is known to be normally distributed with a standard deviation of $2.50.

Mariulka [41]

Answer:

95% Confidence interval for taxi fare: ($20.5,$24.2)

Step-by-step explanation:

We are given the following data set: for fares:

$22.10, $23.25, $21.35, $24.50, $21.90, $20.75, and $22.65

Formula:

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{156.5}{7} = 22.35$

95% Confidence interval:

$\bar{x} \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$22.35 \pm 1.96(\frac{2.5}{\sqrt{7}} ) = 22.35 \pm 1.85 = (20.5,24.2)$

6 0

2 years ago

HELP PLEASE I NEED THIS DONE ASAP

Nata [24]

a). 0.45 with a line over the 45 means 0.45454545454545... forever.

It's equivalent to 45/99 which is <em>5/11</em> .

b). 0.45 with a line over the 5 means 0.455555555... forever.

It's equivalent to (0.4 + 0.555555.../10)

The 0.4 part is 4/10

The 0.5555555555.../10 part is 5/90 .

(4/10) + (5/90) = <em>41/90 </em>

c). 0.45 means 45/100 . That's <em> 9/20</em> .

I don't think you're supposed to be posting unit test questions on Brainly.

6 0

2 years ago

A student earned grades of 84, 78, 84, and 72 out of 100 on her four regular tests. She scored 78% on the final exam and 86% on

adelina 88 [10]

If the student received marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade is 81.2 percent.

The mean is described as a single number that indicates either the closed value for each item in the collection of data or the mean value for the whole set of data.

On her four regular tests, a student had grades of 84, 78, 84, and 72 out of 100. She received 86 percent on her class projects and 78 percent on the final test.

You may compute the weighted mean as follows:

$\rm W_m= 0.4 \times ( \frac{84+78+84+72}{4} )+0.3 \times 78 +0.1 \times 86 + 0.2 \times 87 \\\\ W_m= 81.2 \%$

Hence, if the student had marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade would be 81.2 percent.

To learn more about the mean refer;

brainly.com/question/22871228

#SPJ1

5 0

1 year ago