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2 years ago

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A 2-column table with 4 rows. The first column is labeled x with entries 0, 0.5, 1, 1.5. The second column is labeled y with ent

ries 40, 39.25, 38.5, 37.75. What is the range of this function?

1 answer:

kodGreya [7K]2 years ago

4 0

help me help me help help me help

Step-by-step explanation:

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Please hurry <br> Select all the points that are on the graph of the line<br> 3x + 5y = 20 ?

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Answer:

x=5

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Step-by-step explanation:

3*5=15

5*1=5

15+5=20

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G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$

2. Since

$G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x)$ the function is neither even nor odd.

3. The domain is $x\in (-\infty,\infty),$ the range is $y\in (-\infty,\infty).$

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2 years ago

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To compute the area of a rectangle, you need to use the formula A=l.w if the length is 2 3/4 inches and the width is 4 1/2 inche

blagie [28]

Answer:

12 3/8

Step-by-step explanation:

A = 2 3/4 x 4 1/2

best way is to change mixed numbers to fractions and multiply and then go back to a mixed number.

11/4 x 9/2 = 99/8 = 12 3/8

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