Answer:
L' = 555.95 lb
Explanation:
Analyzing the given conditions in the question, we get
The safe load, L is directly proportional to width (w) and square of depth (d²)
also,
L is inversely proportional length (l) i.e L = k/l
combining the above conditions, we get an equation as:
L = k(wd²/l)
now, for the first case we have been given
w = 3 in
d = 6 in
l = 11 ft
L = 1213 lbs
thus,
1213 lb = k ((3 × 6²)/11)
or
k = 123.54 lbs/(ft.in³)
Now,
Using the calculated value of k to calculate the value of L in the second case
in the second case, we have
w = 6 in
d =3 in
l = 12 ft
Final Safe load L' = 123.54 × (6 × 3²/12)
or
L' = 555.95 lb
<h2>
Answer: Earth's orbital path around the Sun</h2><h2>
</h2>
The <u>Ecliptic</u> refers to the orbit of the Earth around the Sun. Therefore, <u>for an observer on Earth it will be the apparent path of the Sun in the sky during the year, with respect to the "immobile background" of the other stars.</u>
<u />
It should be noted that the ecliptic plane (which is the same orbital plane of the Earth in its translation movement) is tilted with respect to the equator of the planet about 
approximately. This is due to the inclination of the Earth's axis.
Hence, the correct option is Earth's orbital path around the Sun.
Initial speed(u)=0m/s
Final speed(v)= 27m/s
Time(t)=7.6s
Use the equation of motion: v = u + at
27 = 0 + a(7.6)
27/7.6 = a
a = 3.55 m/s^2 (3 s.f)
The term used is " WORK".
I'm really sorry it's not one of the choices.
