PQRS is an isosceles trapezoid and m < Q=127
so m<Q = m<P =127
answer
127
Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]
Answer:
-48
Step-by-step explanation:
Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words
Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,
- M(x,y) = 4x²y
- Mx(x,y) = 8xy
- L(x,y) = 10y²x
- Ly(x,y) = 20xy
- Mx - Ly = -12xy
Therefore, the line integral can be computed as follows
Using the linearity of the integral and Barrow's Theorem we have
As a result, the value of the double integral is -48-
Answer:
one has (_) and another has (+)
Answer:
i. The ratio of the areas of the two triangles is 5:8.
ii. The area of the larger triangle is 24 in².
Step-by-step explanation:
Let the area of the smaller triangle be represented by , and that of the larger triangle by .
Area of a triangle = x b x h
Where; b is its base and h the height.
Thus,
a. The ratio of the area of the two triangles is:
Area of smaller triangle = x b x h
= x 5 x h
= h
Area of the lager triangle = x b x h
= x 8 x h
= 4h
So that;
Ratio =
=
The ratio of the areas of the two triangles is 5:8.
b. If the area of the smaller triangle is 15 in², then the area of the larger triangle can be determined as;
=
=
5 = 15 x 8
= 120
=
= 24
The area of the larger triangle is 24 in².
Answer:
Associative property of addition. Grouping different addends does not change the sum.
Step-by-step explanation:
5 + 2 + 3 = 5 + (2 + 3)
10 = 5 + (5)
10 = 10