Idk this is hard sorry I couldn't help you but you just helped me
Answer:
Step-by-step explanation:
Given: sum of the smallest integer and four times the largest integer out of three consecutive odd integers is 61
To list: numbers from least to greatest
Solution:
Let the three consecutive odd integers be .
According to question,
So, the integers are
Numbers from least to the greatest:
7____ is the one that couldn't used to complete a table of eqiuvalent ratios
For this case we must find the solution set of the given inequalities:
Inequality 1:
Applying distributive property on the left side of inequality:
Subtracting 3 from both sides of the inequality:
Dividing by 6 on both sides of the inequality:
Thus, the solution is given by all the values of "x" greater than 3.
Inequality 2:
Subtracting 3x from both sides of the inequality:
Subtracting 3 from both sides of the inequality:
Thus, the solution is given by all values of x less than 4.
The solution set is given by the union of the two solutions, that is, all real numbers.
Answer:
All real numbers