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2 years ago

7

Rhosanda is downloading a file from the Internet. The size of the file is 7.45 MB. The file is downloading at the rate of 0.095

MB per second. How many seconds will it take to download the entire file? Round your answer to the nearest second.

1 answer:

elixir [45]2 years ago

7 0

7.45/0.095 = 78 seconds

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sarah invests £9600 at a simple interest rate of 8% per year. Work out the value of the investment after 3 years

andre [41]

Answer:

the value of the investment after 3 years= £11,904

Step-by-step explanation:

sarah invests £9600 at a simple interest rate of 8% per year

number of years = 3

Formula for simple interest

I = P*n* r

P is the initial amount invested= 9600

r is the rate of interest = 8% = 0.08

n = number of years = 3

Now we find interest using formula

I = 9600 * 0.08 * 3= 2304

Interest amount is 2,304

Now we add the interest with the initial amount to get the value of investment after 3 years

9600 + 2304= 11904

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2 years ago

Enter the solutions from least to greatest.<br> (2x+4)(3x-2)=0

MArishka [77]

Answer:

From least to greatest: -2, 2/3

Step-by-step explanation:

Set each factor equal to 0 and solve

2x + 4 =0

2x = -4

x = -2

3x - 2 = 0

3x = 2

x = 2/3

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1 year ago

Find the area of the rhombus.<br>8 m<br>8 m<br>8 m<br>8 m

mel-nik [20]

Answer:32 m

Step-by-step explanation: Basically 8*8/2=32 so its just 32 if the sides are 8m

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3 years ago

Prove the divisibility of the following numbers:

Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

$75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}$

(B)

$72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}$

In this case, it is easier to also factor the divisor to primes:

$72^{63}=2^{189}\cdot 3^{126}$

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

$2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}$

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madreJ [45]

Answer:

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Step-by-step explanation:

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