the angular frequency of this motion is 5.46rad /sec
The formula for the angular frequency is = 2π/T. Radians per second are used to express angular frequency. The frequency, f = 1/T, is the period's inverse. The motion's frequency, f = 1/T = ω/2π, determines how many complete oscillations occur in a given amount of time so in this case the It is measured in units of Hertz, (1 Hz = 1/s).
herex
=
(17.4cm)cos[(5.46s− 1)t]
is written in the general form
where we can identify: A=17.4cm and ω
=5.46rad /sec
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Answer:
- The gravity does a work of - 117.6 Joules.
- The tension does not do work as the force is perpendicular to the direction of motion at any point in the trajectory.
Explanation:
The work done by the gravity simply is the difference in gravitational potential energy multiplied by -1:
where m is the mass of the ball, g is the acceleration due to gravity, is the final height and is the initial height.
So, if the radius is 2.00 m, then the difference of height will be 4 meters:
As the tension is perpendicular to the velocity of the ball, the force is always perpendicular to the direction of motion. So, the differential of work will be:
For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.
We can calculate the initial speed to reach 110 cm of height with the following equation:
Where:
: is the final speed = 0 (at the maximum height of 110 cm)
: is the initial speed =?
g: is the acceleration due to gravity = 9.81 m/s²
h: is the height = 110 cm = 1.10 m
Hence, the <u>initial velocity</u> is:
Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.
You can see another example here: brainly.com/question/13359681?referrer=searchResults
I hope it helps you!
Answer:
1.566 x 10^2
Move the decimal to where the number being multiplied by 10^x is greater than 1 but less than 10. Then multiply it by 10^x
X is the number of times you moved the decimal, so in this case it would be 10^2