Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
The pack of pencils weighs 21.6 grams because 0.9 times 24 is 21.6
The length of the shortest side of the hexagon is; 41.833 inches
<h3>How to find the perimeter of a Polygon?</h3>
Let the length of the shortest side of the hexagon be x. Now, a hexagon has six sides and if the next side is 10 inches longer than the previous side, then the length of the six sides are;
x, x + 10, x + 20, x + 30, x + 40, x + 50
Perimeter is given as 401 inches. Thus;
x + x + 10 + x + 20 + x + 30 + x + 40 + x + 50 = 401
6x + 150 = 401
6x = 401 - 150
6x = 251
x = 251/6
x = 41.833 inches
Read more about Polygon Perimeter at; brainly.com/question/14490532
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The answer is 1.
Because if you simplify (divide) 19/19 you get one.
4/4 would also be 1. Any number divided to itself will always be 1.
Whereas 30/15 would be 2 because thirty divided by fifteen is 2
34 = q + n
6.1 = .25q + .05n
-1.7 = -.05q - .05n
6.1 = .25q + .05n
4.4 = .2q
q = 22
22 of the coins are quarters.