Answer:
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- <u><em>The length of the image of the segment GH would be 5 units.</em></u>
Explanation:
You can use the <em>center of dilation</em> as your origin of coordintes.
Thus, the <em>point H</em> would have coordinates (0,0) and the <em>point G</em> (-1,0).
A <em>dilation</em> multiplies the coordinates by the <em>scale factor</em>. Hence:
- H = (0,0) → H' = 5 × (0,0) = (0,0)
- G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)
Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.
Answer:
MLH is congruent to JKI
LNK is congruent to HNI
I think that's how you're supposed to answer it...
Answer:
Step-by-step explanation:
In similar figure all the corresponding angles will be congruent and corresponding sides will be in ratio
Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
Answer:
no
Step-by-step explanation:
there is not one point that is very distant from all of the other ones
