2|3x + 5| = -10 . Divide both sides by 2:
|3x + 5| = -5 ===>3x+5=-5 & -3x-5=-5 In both cases x=0
-10 + a = 6a - 7a
Rearrange the left hand side
a - 10 = 6a - 7a
Simplify 6a - 7a
a - 10 = -a
Add a on both sides
2a - 10 = 0
Add 10 on both sides
2a = 10
Divide by 2 on both sides
a = 5
Answer:
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Step-by-step explanation:
<u>Answer:</u>
<u>Step-by-step explanation:</u>
The sum of interior angles of a quadrilateral is 360°.
If we consider the measure of one of the unknown angles to be °, we can set up the following equation:
Now we can solve for :
⇒
⇒ [subtracting 192° from both sides]
⇒
⇒ [dividing both sides by 2]
⇒
Therefore, the other two angles each have a measure of 84°.
Let x be the length of third side.
12 + x > 13
x > 1-------------(1)
13 + x > 12
x > -1 ------------(2)
by combining (1) and (2)
we have x > -1