Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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Answer: First Option | 2 x 10^1
Reason: After doing 6.4 divided by 3.2, you get 2, and finally you subtract 10³ by 10². And after that subtraction, you get 10^1, Therefore the answer is the first option.
<em>I hope this helps, and Happy Holidays! :)</em>
Answer:
Correct equation: 4b^2 -b-138= 0
Solution: 6 meters
Step-by-step explanation:
The base has to be 6, and that’s the equation that works with that number.
Answer:
Step-by-step explanation:
Newtons third law= every action has a equal and oposite reaction:like if you push a wall u will go backwards.
Quarantine: hmmm
1# Because of the corona viris, we have to stay at home
