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2 years ago

How do you find the slope of a line? (Change in Y / Change in X)

1 answer:

8 0

In order to find the slope of a line, u must use the slope formula. Which is (y2-y1/x2-x1). For example if you had a set of coordinates that are (6,4) and (2,8) you would first sub the 8 from4 which gives you 4. The u do the same with 2 and 6 which gives u 4. After that you divide 4 by 4. and your answer is 1

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What are the values of a and b in the equation

Nat2105 [25]

Answer:

a= -2 b =4

Step-by-step explanation:

I put it in a calculator and found the answer

5 0

2 years ago

Use synthetic division to find (5x<br> + 31x + 32) = (x + 5).

LiRa [457]

We move all terms to the left:
+31x+32)-((+5)=0
So your answer is 0

5 0

2 years ago

What is the opposite of the number -2 1/3 ?

Katyanochek1 [597]

The opposite of the number -2 1/3 is 2 1/3 because if you look at a number line you will see that -2 1/3 and 2 1/3 are on opposite sides of the line

4 0

2 years ago

Read 2 more answers

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

2 years ago

(5 pts) A quadratic function f is given by f(x) = ax2 + bx + c where a is not 0. Select all

Vsevolod [243]

Answers:

a) True. Plug in x = 0 and it leads to y = c. Therefore, the point (0,c) is on the parabola.
b) False. Plug in y = 0 and apply the quadratic formula. One x intercept may sometimes be x = c, but it could easily be other values as well. Or perhaps you may not get any real number solutions at all. See part d) below.
c) True. If a < 0, then the leading coefficient is negative. Overall, both endpoints will tend toward negative infinity to produce a parabola that opens downward.
d) False. The quadratic may have one x intercept or it may not have any x intercepts at all. It depends on what the discriminant d = b^2 - 4ac is equal to. If d < 0, then we have no x intercepts. If d = 0, then we have exactly 1 x intercept. If d > 0, then we have two different x intercepts.
e) True. The vertex's x coordinate is -b/(2a). If b = 0, then the x coordinate of the vertex is 0. The vertical line x = 0 is directly on top of the y axis.

8 0

2 years ago