<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
A sum of $104 is divided among three friends Adam, Charlie and Max in the ratio 3 : 4 : 6. How much more money does Max have than Adam ?
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Ratio = 3 : 4 : 6 (Given)
Let the sum of Adam be 3x
Let the sum of Charlie be 4x
Let the sum of Max be 6x
Total sum = $104 (Given)
So,
<u>A</u><u>T</u><u>Q</u> ,
3x + 4x + 6x = 104
13x = 104
x =
<h3>x = 8</h3>
Now, total sum of Adam = 3x = 3 × 8 = $24
Total sum of Max = 6x = 6 × 8 = $48
Required money Max have more than Adam = (48 - 24) = $24
<h3><u>$</u><u>2</u><u>4</u> money does Max have more than Adam. [Answer]</h3>