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2 years ago

Which will result in a difference of squares? (–7x + 4)(–7x + 4) (–7x + 4)(4 – 7x) (–7x + 4)(–7x – 4) (–7x + 4)(7x – 4)

Mathematics

2 answers:

stealth61 [152]2 years ago

6 0

Answer:

(–7x + 4)(–7x – 4) Sign changes in the middle of both parenthesis , so this will result in difference of squares

Step-by-step explanation:

The formula for difference of squares

$a^2 - b^2 =(a+b)(a-b)$

(–7x + 4)(–7x + 4) both parenthesis having same terms so this will not result in difference of squares

(–7x + 4)(4 – 7x) both parenthesis having same terms so this will not result in difference of squares

(–7x + 4)(–7x – 4) Sign changes in the middle of both parenthesis , so this will result in difference of squares

(–7x + 4)(7x – 4) sign changes for both terms in both parenthesis so this will not result in difference of squares

denpristay [2]2 years ago

4 0

a difference of squares
a^2 – b^2 = (a + b)(a – b)
in this case

(–7x + 4)(–7x – 4)

answer
(–7x + 4)(–7x – 4)

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kiruha [24]

Answer:

Dear User,

Answer to your query is provided below

The time will be 8am on Wednesday when flight arrive in Tokyo.

Step-by-step explanation:

Here, You can see that when 11 a.m. in Johannesburg, it is 6 p.m. the same day in Tokyo, Japan ; this means 7Hrs. gap.

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A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%

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Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

Step :- (i)

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

95% of confidence intervals

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$

Step:-(ii)

The degrees of freedom γ=n-1 = 15-1=14

The tabulated value t = 1.761 at 0.05 level of significance.

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Conclusion:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

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