What is the length of BC in the right triangle below
2 answers:
Answer:
<h2><em>1</em><em>5</em><em> </em><em>units</em></h2><em>The </em><em>length </em><em>of </em><em>BC </em><em>is </em><em>1</em><em>5</em><em> </em><em>units.</em>
<em>Solution,</em>
<em>Hypotenuse(</em><em>h)</em><em>=</em><em>?</em>
<em>perpendicular(</em><em>p)</em><em>=</em><em>1</em><em>2</em>
<em>base(</em><em>b)</em><em>=</em><em>9</em>
<em>Using </em><em>Pythagoras</em><em> </em><em>theorem</em><em>,</em>
<em></em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>
You might be interested in
The equation of a circle in standard form is
where (h, k) is the center of the circle, and r is the radius if the circle.
We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.
M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).
To find the radius, we find the length of the given diameter and divided by 2.
where (h, k) is the center of the circle, and r is the radius if the circle.
We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.
M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).
To find the radius, we find the length of the given diameter and divided by 2.