Px-2= 4x+x+9
First what you should do is subtract the 2 on both sides
You’ll get px = 4x+x+7 then add the x to 4x
Px= 4x^2 +7
Dived the x on the left on both sides like this px/x = 4x^2+7/x
P= 4x+7
16.4 is going to round to 16 because anything less than 0.5 rounds down.
Complete Question
Two different red-light-running signal systems were installed at various intersection locations with the goal of reducing angle-type crashes. Red-Light-Running System A resulted in 60% angle crashes over a sample of 720 total crashes. Red-Light-Running System B resulted in 52% angle crashes over a sample of 680 total crashes. Was there a difference between the proportions of angle crashes between the two red-light-running systems installed? Use an alpha of 0.10.
Answer:
Yes there is a difference between the proportions of angle crashes between the two red-light-running systems installed
Step-by-step explanation:
From the question we are told that
The first sample proportion is
The second sample proportion is
The first sample size is
The second sample size is
The level of significance is
The null hypothesis is
The alternative hypothesis is
Generally the pooled proportion is mathematically represented as
=>
=>
Generally the test statistics is evaluated as
The p-value obtained from the z-table is
From the question we see that so the null hypothesis is rejected
Hence we can conclude that there is a difference between the proportions
Answer:
x = 1/14
Step-by-step explanation:
You can work it as is by subtacting ln(14), then taking antilogs:
ln(x) = -ln(14)
x = 14^-1
x = 1/14
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Or you can rewrite to a single log and then take antilogs:
ln(14x) = 0
14x = 1
x = 1/14 . . . . . divide by the coeffient of x