Answer:
the probability that all tomatoes are sold is 0.919 (91.9%)
Step-by-step explanation:
since the random variable X= number of tomatoes that are demanded, is normally distributed we can make the standard random variable Z such that:
Z=(X-μ)/σ = (83 - 125)/30 = -1.4
where μ= expected value of X= mean of X (since X is normally distributed) , σ=standard deviation of X
then all tomatoes are sold if the demand surpasses 83 tomatos , therefore
P(X>83) = P(Z>-1.4) = 1- P(Z≤-1.4)
from tables of standard normal distribution →P(Z≤-1.4)=0.081 , therefore
P(X>83) = 1- P(Z≤-1.4) = 1 - 0.081 = 0.919 (91.9%)
thus the probability that all tomatoes are sold is 0.919 (91.9%)
It should be 18, because despite of 3,14, because that's pi and radius is half of the diameter, so36 divide 2 is 18.
Answer:
Step-by-step explanation:
Applying the Laplace transform:
![\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%2B5%5Cmathcal%7BL%7D%5By%27%5D%2B4%5Cmathcal%7BL%7D%5By%27%5D%3D0)
With the formulas:
![\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%27%5D%3Ds%5E2%5Cmathcal%7BL%7D%5By%5D-y%280%29s-y%27%280%29)
![\mathcal{L}[y']=s\mathcal{L}[y]-y(0)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5By%27%5D%3Ds%5Cmathcal%7BL%7D%5By%5D-y%280%29)
![\mathcal{L}[x]=L](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bx%5D%3DL)
Solving for 
Apply the inverse Laplace transform with this formula:
![\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs-a%7D%5D%3De%5E%7Bat%7D)
![y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}](https://tex.z-dn.net/?f=y%3D3%5Cmathcal%7BL%7D%5E%7B-1%7D%5B%5Cfrac1%7Bs%2B4%7D%5D%3D3e%5E%7B-4t%7D)
Answer:
534 is the mean.
Step-by-step explanation:
to calculate the mean you add all the numbers together (for example this set of numbers):
785, 585, 465, 409, 495, 465
=3204
then divide the number of numbers that you added together , (in this case 6)
3204/6
=
534
C
A million apologies if I’m incorrect
