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2 years ago

Please help me!!

Mathematics

1 answer:

andrey2020 [161]2 years ago

5 0

Answer:

(A.)

Step-by-step explanation:

Hope it helps :)

Have a good day/night

Brainliest pls?

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Which expression represents a number that is 4 times as great as the quotient of 25 and 5? A. ( 25 × 5 ) × 4 B. 4 ÷ ( 25 × 5 ) C

oksano4ka [1.4K]

Answer:

It would be D.

4 0

2 years ago

Read 2 more answers

Five years from now, the sum of the ages of a women and her daughter will be 40 years. The difference in their present age is 24

Tomtit [17]

Answer:

Daughter age = 3 years

Step-by-step explanation:

Let x be the age of the women and y be the age of the daughter.

Given:

After five year the sum of the women and daughter age = 40

$(x+5)+(y+5)=40$

At present the sum of the women and daughter age

$x+5+y+5=40$

$x+y+10=40$

$x+y=40-10$

$x+y=30$ --------------(1)

So the sum of the present age is $x+y=30$

The difference in their present age is 24 years.

$x-y=24$

$x=24+y$

Now we substitute x value in equation 1.

$(24+y)+y=30$

$24+2y=30$

$2y=30-24$

$2y=6$

$y=\frac{6}{2}$

$y=3\ years$

Therefore, the daughter age is 3 years.

7 0

2 years ago

7. The basic pay categories, hourly rates of pay and the number of

Ronch [10]

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2 years ago

Please help me 33/2 + 3y/5 = 7y/10 + 15

8090 [49]

We are given with an equation in variable y and we need to solve for y . So , now let's start !!!

We are given with ;

${:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}$

Take LCM on both sides :

${:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}$

Multiplying both sides by 10 ;

${:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}$

${:\implies \quad \sf 165+6y=7y+150}$

Can be further written as ;

${:\implies \quad \sf 7y+150=165+6y}$

Transposing 6y to LHS and 150 to RHS

${:\implies \quad \sf 7y-6y=165-150}$

${:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}$

8 0

1 year ago

Mhanifa can you please help? Look at the picture attached. I will mark brainliest!

Nikitich [7]

Answer:

Given rhombus ABCD with

m∠EAD = 67°, CE = 5, DE = 12

Properties of a rhombus:

All sides are congruent
Diagonals are perpendicular
Diagonals are angle bisectors
Diagonals bisect each other

Solution, considering the above properties

1. m∠AED = 90°, as angle between diagonals
2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
4. AE = CE = 5, as E is midpoint of AC
5. BE = DE = 12, as E is midpoint of BD

4 0

2 years ago