Answer:
- <em>m</em> =
- <em>μ</em> = 20
- <em>σ </em>= 20
The probability that a person is willing to commute more than 25 miles is 0.2865.
Step-by-step explanation:
Exponential probability distribution is used to define the probability distribution of the amount of time until some specific event takes place.
A random variable <em>X</em> follows an exponential distribution with parameter <em>m</em>.
The decay parameter is, <em>m</em>.
The probability distribution function of an Exponential distribution is:
<u>Given</u>: The decay parameter is,
<em>X</em> is defined as the distance people are willing to commute in miles.
- The decay parameter is <em>m</em> = .
- The mean of the distribution is: .
- The standard deviation is:
Compute the probability that a person is willing to commute more than 25 miles as follows:
Thus, the probability that a person is willing to commute more than 25 miles is 0.2865.
Answer:
Please see the attached file for the complete answer.
Step-by-step explanation:
If we break the answer down, we can solve this pretty easily.
We can represent Dic's age with x.
Tom's age is 5 MORE (+5) than TWICE (2x) Dic's age (x)
Therefore, our answer is 5+2x (Five more than twice Dic's age)
The correct answer is C: 5+2x
Answer:
Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?
Answer:
Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.
Step-by-step explanation:
We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.
<em>Let X = incomes for the industry</em>
So, X ~ N()
Now, the z score probability distribution is given by;
Z = ~ N(0,1)
where, = mean income of firms in the industry = 95 million dollars
= standard deviation = 5 million dollars
So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)
P(X < 100) = P( < ) = P(Z < 1) = 0.8413 {using z table]
Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.