All categories

2 years ago

Algebra 2 help please.

Mathematics

1 answer:

Oksanka [162]2 years ago

4 0

$\frac{\sqrt{4^{3}}\sqrt[3]{x}\sqrt{y}}{\sqrt{z}} * \frac{\sqrt[5]{y^{2}}\sqrt[3]{z}}{\sqrt{x^{4}}} * \frac{\sqrt[5]{x^{3}}\sqrt[4]{x^{6}}}{\sqrt[3]{y^{2}}}$
$\frac{\sqrt{64}\sqrt[3]{x}\sqrt{y}}{\sqrt{z}} * \frac{\sqrt[5]{y^{2}}\sqrt[3]{z}}{x^{2}} * \frac{x^{2}\sqrt[5]{x^{3}}\sqrt[4]{x^{2}}}{\sqrt[3]{y^{2}}}$
$\frac{8\sqrt[3]{x}\sqrt{y}}{\sqrt{z}} * \frac{\sqrt[5]{y^{2}}\sqrt[3]{z}}{x^{2}} * \frac{x^{2}\sqrt[5]{x^{3}}\sqrt[4]{x^{2}}}{\sqrt[3]{y^{2}}}$
$\frac{8\sqrt{y}\sqrt[3]{xz}\sqrt[4]{x^{2}}\sqrt[5]{x^{3}y^{2}}}{\sqrt{z}\sqrt[3]{y^{2}}}$
$\frac{8\sqrt{yz}\sqrt[3]{xy^{2}z}\sqrt[4]{x^{2}}\sqrt[5]{x^{3}y^{2}}}{y^{2}z}$

You might be interested in

Please help! .........

stira [4]

Answer:

1) When x is 1, y is 4, and vice versa

2) When x is -6, y is 42, and when x is 7, y is 114

3) When x is -2, y is 2, and when x is 8, y is 42

Step-by-step explanation:

$y=x^2-6x+9$

$y+x=5$ which can be rearranged as $y=5-x$ .

Substituting this lone y into the first equation, you get:

$5-x=x^2-6x+9$

Move everything to one side:

$x^2-5x+4=0$

Factor:

$(x-4)(x-1)=0$

$x=1, 4$

$y=4, 1$

$y-30=12x$ which can be rearranged as $y=12x+30$ .

$y=x^2+11x-12$

Let's use elimination this time and subtract the first equation from the second:

$0=x^2-x-42$

Factor:

$(x-7)(x+6)=0$

$x=-6, 7$

$y= -42, 114$

$y=x^2-2x+6$

$y=4x+10$

Let's set the two equations equal to each other through substitution:

$x^2-2x-6=4x+10$

Move everything to one side:

$x^2-6x-16=0$

Factor:

$(x-8)(x+2)=0$

$x=-2, 8$

$y= 2, 42$

Hope this helps!

6 0

2 years ago

Which one of these is not like the others? [Things to think about, but not limited to…… what way does the graph open? Signs of t

user100 [1]

Answer:Function3

Step-by-step explanation:

4 0

2 years ago

if j is 21 inches, k is 12 inches, and angle M measures 62 degrees, then find m using the Law is Cosines. round your answer to t

AURORKA [14]

Answer:

18.7

Step-by-step explanation:

The Law of Cosines is $c^2=a^2+b^2-2ab cos(C)$ , where c is the unknown side length of a triangle, a and b are the remaining two side lengths, and C is the angle opposite to side c. To answer this question just plug in the known values: