Answer is:
4-ethyl-1-heptene.Structure of this alkene is in Word document attached.
<span>First find main chain with longest number of carbon atoms, that is chain with seven carbon atoms and it start on the right and going up the three-carbon attachment.
Main chain has double bond between first and second carbon (</span><span>the lowest number)</span><span>, so it is 1-heptene (alkene).
</span>Substituent is on fourth carbon atom, it is alkyl group with two carbon atoms (ethyl).
Answer:
Kc = 0.075
Explanation:
The dissociation (α) is the initial quantity that ionized divided by the total dissolved. So, let's calling x the ionized quantity, and M the initial one:
α = x/M
x = M*α
x = 0.354M
For the stoichiometry of the reaction (2:1:1), the concentration of H₂ and I₂ must be half of the acid. So the equilibrium table must be:
2HI(g) ⇄ H₂(g) + I₂(g)
M 0 0 <em> Initial</em>
-0.354M +0.177M +0.177M <em>Reacts</em>
0.646M 0.177M 0.177M <em>Equilibrium</em>
The equilibrium constant Kc is the multiplication of the products' concentrations (elevated by their coefficients) divided by the multiplication of the reactants' concentrations (elevated by their coefficients):
Kc = 0.075
Answer:
C the number and placement of the electrons
Explanation:
Elements react with one another because they want to achieve a full valence shell of electrons. The noble gases already have a full valence shell of electrons, so they are unlikely to react with other elements.
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Answer:
1.126 x 10^22
Explanation:
pV = nRT
7.53 x 10 = n x 8.31 x 485
n = (7.53 x 10) / (8.31 x 485) = 0.0187 moles
M = n x Avogadros number
0.0187 x 6.02 x 10^23 = 1.126 x 10^22