Answer:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Explanation:
- Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).
- Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)
Writing the equation using symbols leaves us with:
- Fe + CuNO₃ → Fe(NO₃)₃ + Cu
<em>It is not balanced yet</em>. Now we <u>balance the NO₃ species on the left side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu
Finally we<u> balance the Cu species on the right side</u>:
- Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
Answer:
B. Equal to 7.
Explanation:
Hydrobromic acid is a strong acid that decreases pH and ammonia is a strong base that increases pH.
As the initial pH of water is 7,0 the addition of 35.0mL of 0.400M HBr will produce a pH less than 7,0. But, the same effect of decreasing pH is reverted for the addition of 35.0mL of 0.400M HNO3.
That means the net effect of the two addition is to have a pH:
B. Equal to 7.
I hope it helps!
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