Ask question

Ask question

All categories

2 years ago

12

The chemical equation shown represents photosynthesis. Carbon dioxide plus A plus light with a right-pointing arrow towards B pl

us oxygen. The arrow has an x above it. What is the role of substance B in photosynthesis?
It stores chemical energy.
It converts light into chemical energy.
It traps light energy from the atmosphere.
It cools the atmosphere by changing into vapor.

2 answers:

babunello [35]2 years ago

6 0

The answer is a. i think

AysviL [449]2 years ago

4 0

I don't know the exact answer but I know it is NOT D or C, I am shooting for A but I may be wrong. A

You might be interested in

A. What evidence have you discovered to explain how

svp [43]

Answer:

Well if it gets warmer the ice will weaken and if it gets hot enough will melt. Of course if the weather gets colder the ice will thicken.

Explanation:

3 0

2 years ago

Read 2 more answers

An apple with mass 0.4 kg is hanging at rest from the lower end of a light vertical rope. A dart of mass 0.1 kg is shot vertical

Sholpan [36]

Answer:

The speed of the apple just after the collision is 1m/s

Explanation:

Since the two bodies collided, we will apply the law of conservation of momentum to find their common velocity which states that the sum of momentum of the bodies before collision is equal to the sum of momentum of the bodies after collision. After collision both bodies will move with a common velocity v.

Given momentum = mass × velocity

Initial momentum of the 0.4kg apple hanging at rest will be;

Momentum = 0.4kg×0m/s = 0kgm/s (the velocity of apple is 0m/s since it is hanging at rest)

Initial momentum of the 0.1kg dart moving with speed of 5m/s will be;

Momentum of dart = 0.1kg × 5m/s

Momentum of dart = 0.5kgm/s

Momentum of the bodies after collision will give;

Momentum after collision = (0.4kg+0.1kg) × v (v is their common velocity)

Momentum after collision = 0.5v

Using the law of conservation of momentum to calculate their common velocity, we will have;

0+0.5 = 0.5v

0.5 = 0.5v

v = 0.5/0.5

v = 1m/s

Therefore the speed of both bodies after collision is 1m/s which will also serve as the speed of the apple after collision.

5 0

2 years ago

Read 2 more answers

A)If your torsion balance deflects to an angle of 10° when your two spheres are 40cm apart, what angle will it deflect to when t

svp [43]

Answer:

Explanation:

Given

for $\theta=10^{\circ}$

Sphere are $d=40\ cm$

when sphere $d_2=10\ cm$ apart suppose deflection is $\theta _2$

We know

$F=k_t\cdot \theta$

Where F=force between charged particle

$\theta =$ Deflection

$F=\frac{kQ_1Q_2}{r^2}=k_t\cdot \theta$

$\theta =\frac{k}{k_t}\times \frac{Q_1Q_2}{r^2}----1$

thus $\theta \propto \frac{1}{r^2}$

for $\theta _2$

$\frac{\theta _1}{\theta _2}=(\frac{r_2}{r_1})^2$

$\theta _2=16\times \theta _1$

$\theta _2=160^{\circ}$

(b)for $10^{\circ}$ deflection Potential $v_1=8\ kV$

Electric Potential is $V=\frac{kQ}{r}$

$Q=\frac{V\cdot r}{k}$

where V=voltage

k=constant

r=distance between charges

Put value of Q in equation 1

$\theta =\frac{k}{k_t}\times \frac{V^2r^2}{k^2}$

$\theta =\frac{V^2r^2}{k\cdot k_t}$

thus $\theta \propto V^2$

therefore

$\frac{\theta _1}{\theta _2}=(\frac{V_1}{V_2})^2$

$\frac{10}{\theta _2}=(\frac{8}{4})^2$

$\theta _2=\frac{10}{4}=2.5^{\circ}$

5 0

2 years ago

For an RLC circuit in the limit of very high frequency, what is the effective behavior of the capacitor and the inductor in the

Aliun [14]

Answer:

Explanation:

Given

In R-L-C circuit frequency is very high

Inductive Reactance for inductor is given by $X_L=2\pi f\cdot L$

Inductive Reactance for Capacitor is given by $X_c=\frac{1}{2\pi f\cdot C}$

as frequency becomes too high then $X_L$ will become very large and and $X_c$ will be approximately zero .

In other words inductor behave as a very high resistance and Capacitor behaves as very small resistance

3 0

2 years ago

The figure shows five electric charges. Four charges with the magnitude of the charge 2.0 nC form a square with the size a = 4.0

bearhunter [10]

Considering the four electric charges forming a square with magnitude of charge of 2.0 nC on each. :

A) Magnitude of the force on the 5.5 nC charge in the middle of the figure = 3.48 * 10^-4 N

B) Direction of the force on the 5.5 nC charge in the middle of the figure = Leftward ( negative x -axis )

Using the given data :

size of square = 4 cm

magnitudes of four charges = 2.0 nC

<u> a) </u><u>magnitude</u><u> of the force on the center charge </u>

Electric force between two point charges = $F = \frac{1}{4\pi *E_{o} } \frac{q1q2}{r^2}$ ----- ( 1 )

where ; $\frac{1}{4\pi E_{o} } = 9 * 10^9 Nm^2/C^2$

step 1 ; find r ( distance between charges )

r² = ( 2 )² + ( 2 )² = 8 cm²

back to equation 1

F = 9 * 10⁹ * $\frac{2 * 10^{-9} * (5.5 * 10^{-9}) }{8*10^{-4} }$ = 1.23 * 10^-4 N

∴ magnitude of the force on the center charge ( Fnet )= 4F cos 45°

= 4 * ( 1.23 * 10^-4 ) * $\frac{1}{\sqrt{2} }$ = 3.48 * 10^-4 N

b) The direction of the force at the center is along the negative x-axis ( leftward )

Learn more : brainly.com/question/24139734

6 0

2 years ago