Explain what is meant by “field” and compare the properties of gravitational, electric, and magnetic forces in terms of particle
1 answer:
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Answer:
the force of attraction between the two charges is 4.2 x 10⁹ N.
Explanation:
Given;
the magnitude of first charge, q₁ = 0.06 C
the magnitude of the second charge, q₂ = 0.07 C
distance between the two charges, r = 3 m
The force of attraction between the two charges is calculated as ;
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/C²
Therefore, the force of attraction between the two charges is 4.2 x 10⁹ N.
Answer:
Explanation:
This problem is approached using Coulomb's law of electrostatic attraction which states that the force F of attraction or repulsion between two point charges, and
is directly proportional to the product of the charges and inversely proportional to the square of their distance of separation R.
where k is the electrostatic constant.
We can make k the subject of formula as follows;
Since k is a constant, equation (2) implies that the ratio of the product of the of the force and the distance between two charges to the product of charges is a constant. Hence if we alter the charges or their distance of separation and take the same ratio as stated in equation(2) we will get the same result, which is k.
According to the problem, one of the two identical charges was altered from to
and their distance of separation from
to
, this also made the force between them to change from
to
. Therefore as stated by equation (2), we can write the following;
Therefore;
From equation (4) we now make the new force the subject of formula as follows;
then cancels out from both side of the equation, hence we obtain the following;
From equation (4) we can now write the following;
This could also be expressed as follows;
Answer:
1
When second polarizer is removed the intensity after it passes through the stack is
2 When third polarizer is removed the intensity after it passes through the stack is
Explanation:
From the question we are told that
The angle of the second polarizing to the first is
The angle of the third polarizing to the first is
The unpolarized light after it pass through the polarizing stack
Let the initial intensity of the beam of light before polarization be
Generally when the unpolarized light passes through the first polarizing filter the intensity of light that emerges is mathematically evaluated as
Now according to Malus’ law the intensity of light that would emerge from the second polarizing filter is mathematically represented as
The intensity of light that will emerge from the third filter is mathematically represented as
making the subject of the formula
Note that as
is the last emerging intensity of light after it has pass through the polarizing stack
Substituting values
When the second is removed the third polarizer becomes the second and final polarizer so the intensity of light would be mathematically evaluated as
is the intensity of the light emerging from the stack
substituting values
When the third polarizer is removed the second polarizer becomes the
the final polarizer and the intensity of light emerging from the stack would be
is the intensity of the light emerging from the stack
Substituting values