A) Agreed.
<span>b) Value agreed but units should be W (watts). </span>
<span>c) Here's one method... </span>
<span>15 miles = 24140 m </span>
<span>1 gallon of gasoline contains 1.4×10⁸ J. </span>
<span>So moving a distance of 24140m requires gasoline containing 1.4×10⁸ J </span>
<span>Therefore moving a distance of 1m requires gasoline containing 1.4×10⁸/24140 = 5800 J </span>
<span>Overcoming rolling resitance for 1m requires (useful) work = force x distance = 1000x1 = 1000J </span>
<span>So 5800J (in the gasoline) provides 1000J (overcoming rolling resistance) of useful work for each metre moved. </span>
<span>Efficiency = useful work/total energy supplied </span>
<span>= 1000/5800 </span>
<span>= 0.17 (=17%) </span>
Answer:
0.25m/s
Explanation:
Given parameters
m₁ = 5kg
v₁ = 1.0m/s
m₂ = 15kg
v₂ = 0m/s
Unknown:
velocity after collision = ?
Solution:
Momentum before collision and after collision will be the same. For inelastic collision;
m₁v₁ + m₂v₂ = v(m₁ + m₂)
Insert parameters and solve for v;
5 x 1 + 15 x 0 = v (5 + 15 )
5 = 20v
v = 
= 0.25m/s
Answer: Constructive interference
Explanation: Just took the test
Answer:
d)energy
Explanation:
Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.
Answer:
Explanation:
change in the volume of the gas = 5.55 - 1.22
= 4.33 X 10⁻³ m³
external pressure ( constant ) P = 1 x 10⁵ Pa
work done on the gas
=external pressure x change in volume
= 10⁵ x 4.33 X 10⁻³
=4.33 x 10²
433 J
Using the formula
Q = ΔE + W , Q is heat added , ΔE is change in internal energy , W is work done by the gas
Given
Q = - 124 J ( heat is released so negative )
W = - 433 J . ( work done by gas is negative, because it is done on gas )
- 124 = ΔE - 433
ΔE = 433 - 124
= 309 J
There is increase of 309 J in the internal energy of the gas.
