Answer:
F = 1.099N
Explanation:
See the attachment below.
A 100-m long transmission cable is suspended between two towers. If the mass density is 2. 01 kg/m and the tension in the cable
1 answer:
The speed of transverse waves on the cable is 60.26 m/s.
Given,
μ=2.01kg/m, L=100m, T=N
Speed(v)==
=60.26m/s
The speed of an object, sometimes known as "v" in daily speech and kinematics, is a scalar quantity that measures how much its position changes over time or how much it changes per unit of time. The distance traveled by an object during a time interval is equal to the duration of the interval divided by the object's speed, with the instantaneous speed being the upper limit of the average speed as the interval's duration becomes closer to zero. Velocity differs from speed.
Distance divided by time is the formula for measuring speed. A metre per second (m/s) is the metric unit of speed.
Learn more about speed here:
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Answer:
R = 1.2295 10⁵ m
Explanation:
After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body
θ = 1.22 λ / D
where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture
how angles are measured in radians
θ = y / R
where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens
R =
let's calculate
R =
R = 1.2295 10⁵ m