(a) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.11 + 0.52 + 0.19 = 0.82
(b) P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.52 + 0.19 + 0.12 + 0.06 = 0.89
(c) µ = 0×0.11 + 1×0.52 + 2×0.19 + 3×0.12 + 4×0.06 = 1.5
(d) σ² = (0²×0.11 + 1²×0.52 + 2²×0.19 + 3²×0.12 + 4²×0.06) - µ² = 1.07
σ = √(σ²) ≈ 1.03
Answer:
The answer is B
Step-by-step explanation:
hope that helps
Answer:
Step-by-step explanation:
You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.
You will find when you look on your trig identity sheet that
so we will make that replacement, getting everything in terms of sin:
Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:
We can factor out the sin(theta), since it's common in both terms:
Because of the Zero Product Property, either
or
Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:
The next equation needs to first be solved for sin(theta):
so
and
Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:
Answer:
A
Step-by-step explanation:
Correct answer: y=(2/3)x
The line passes through the origin (0,0) and the pair (3,2)
the equation y=(2/3)x satisfies both points:
for (0,0): 0=(2/3)*0 = 0
for (3,2): 2 = (2/3)*3 = 2
and therefore is the correct linear function of the line described.