1 year ago

Suppose we have a linear equation relating y and x defined by

Mathematics

1 answer:

Alexxandr [17]1 year ago

8 0

Answer:

(a) f(x) = -3x +6

Step-by-step explanation:

Solve for y, then write as a function.

3y +9x = 18 . . . . . . given

y +3x = 6 . . . . . . . . divide by 3

y = -3x +6 . . . . . . . subtract 3x

f(x) = -3x +6 . . . . . written using function notation

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Answer:

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Step-by-step explanation:

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64 POINT QUESTION<br><br> √(5-2x) - √(2-x) = 1

Ivanshal [37]

Answer:

x = 2 and x = -2

Step-by-step explanation:

The easiest way is to guess. We know that you can't have a square root of a negative number. This constrains x between negative infinity to 2. Testing 2 and -2, we see that it satisfy the equation.

The more systematic approach is shown below

$\sqrt{5-2x}-\sqrt{2-x}=1 \\\sqrt{5-2x}-\sqrt{2-x}+\sqrt{2-x}=1+\sqrt{2-x} \\\sqrt{5-2x} = 1+\sqrt{2-x}$

$5-2x=(1+\sqrt{2-x})^2\\5-2x=1+2\sqrt{2-x}+2-x\\2-x=2\sqrt{2-x}\\1-0.5x=\sqrt{2-x}\\(1-0.5x)^2=2-x\\1-x+0.25x^2=2-x\\0.25x^2-1=0\\0.25x^2 = 1\\x^2 = 4\\x = +/-2$