The computation for molarity is:
(x) (0.175 L) = 0.0358 g / 598 g/mol
x = 0.000342093 M
Whereas the osmotic pressure calculation:
pi = iMRT
pi = (1) (0.000342093 mol/L) (0.08206 L atm / mol K) (298 K)
pi = 0.0083655 atm
Converting the answer to torr, will give us:
0.0083655 atm times (760 torr/atm) = 6.35778 torr
which rounds off to 6.36 torr
2H2 + O2 = 2H2O since two elements created a compound, in this case water.
Answer and explanation;
-Bromine molecule (Br2) consists of two bromine atoms (Br-Br). These two atoms may be originated from the same type of isotopes Br2(11) and Br2(22) or from two types of isotopes, Br2(12).
The intensity of the peak depends on the abundance of the isotope. The larger the intensity of the peak, the greater the abundance of the isotope. For Br, the relative size of the peak for Br 2 molecule consisting of two different isotopes will be larger than the Br molecule consisting of same isotopes, i.e relative size of the peak for Br molecules consisting of different isotopes is twice as that of Br molecule consisting of same isotopes.
-Hence, from the data in the table we could say that the peak of mass 157.836 represents 79Br - Br peak, 159.834 represents Br - Br peak and peak of mass 161.832 represents Br - 81 81 Br
-The first peak will represent the lighter Br2 molecule, the third peak will represent the heavier Br2 molecules and the middle peak will represent the intermediate Br2 molecule which is Br2(12) .
What is the specific heat of a substance whose mass is 7 grams, if it absorbs 180 calories to go from 10 degrees Celsius to 85 degrees Celsius
Answer:
0.343cal/g°C
Explanation:
Given parameters:
Mass of substance = 7g
Quantity of heat absorbed = 180calories
Initial temperature = 10°C
Final temperature = 85°C
Unknown:
Specific heat of the substance = ?
Solution:
To solve this problem, the specific heat of a substance is the amount of heat needed to raise the temperature of a unit mass of that substance by 1°C.
Mathematically;
C = 
C is the specific heat
Q is the amount of heat
m is the mass
T is the temperature
1 and 2 are the initial and final states
Now, insert the parameters and solve;
C = 
= 0.343cal/g°C
