All categories

1 year ago

The volume of the cube is given as V= x³, where x is the side length of the cube. Find the domain of the volume of

Mathematics

1 answer:

katovenus [111]1 year ago

7 0

Answer: None of the choices

Step-by-step explanation:

1. It couldn't be integers (whole numbers positive or negative), because a cube couldn't have a negative volume.

2. It could be natural numbers, but the problem is, that a volume could have decimal values, for example, 3.62 meters cubed which a natural number doesn't support.

3. Set of whole numbers is the same as integers, so it can't be that.

4. None of the choices, which in my opinion is the correct one.

I'm not sure it is correct, but I hope I helped you!

You might be interested in

Justify Reasoning Determine whether 3x + 12 + x is equivalent to 4(3 + x). Use properties of operations to justify your answer.

Orlov [11]

For 3x + 12 + x, do like terms:
4x + 12
For 4(3 + x), multiply
12 + 4x
They are both the same, just written in different ways. One is adding like terms and the other is multiplying with parentheses. Even though it may be switched around, it is still the same.

Hope this helps :)

4 0

2 years ago

C − 5.5 ≤ 5.5 inequality

Natali5045456 [20]

Answer:

$c\leq 11$

Step-by-step explanation:

5 0

2 years ago

What is the solution set of 12x^2-9x=0??

netineya [11]

12x²-9x = 0
3x(4x-3)=0
4x-3=0
4x=3
x=3/4
so either x = 0 or x = 3/4

6 0

2 years ago

Solve the inequality. –8 ≤ 2x – 4 < 4

Nostrana [21]

First;
-8≤2x-4
-4≤2x
-2≤x

Then;
2x-4<4
2x<8
x<4

-2≤x<4
C is the correct answer.

4 0

2 years ago

Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin

Sidana [21]

Answer:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sigma)$

Where $\mu$ the mean and $\sigma$ the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = \mu$

$\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}$

6 0

2 years ago

Read 2 more answers