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Answer:
C. 25/6 ft²
Step-by-step explanation:
Let's call the dimensions of Rectangle B x and y. Then ...
xy = 5 ft²
and
x² = 6 ft²
We want to find the value of y². Solving the first equation for y, then substituting for x², we have ...
y = (5 ft²)/x
y² = ((5 ft²)/x) = 25 ft⁴/x² = 25 ft⁴/(6 ft²)
y² = (25/6) ft² . . . . . . . matches choice C
I am bad at this types of questions but will give you what i would write of the question if i had it
If his run is 16/8 miles per day, 8/10 of the run is 16/8×8/10= 2×8/10
= 16/10
= 1.6
but... i am not sure if the question requires yoi to add the miles from the pervious day as the break was only stated in the second day. If i were you, i will leave the answer as 1.6 miles.
If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
He wants to buy flowers for me lol
