Answer:
The strongest force that exists between molecules of Ammonia is <em>Hydrogen Bonding</em>.
Explanation:
Hydrogen Bond Interactions are those interactions which are formed between a partial positive hydrogen atom bonded directly to most electronegative atoms (i.e. F, O and N) of one molecule interacts with the partial negative most electronegative atom of another molecule.
Hence, in ammonia the nitrogen atom being more electronegative element than Hydrogen will be having partial negative charge and making the hydrogen atom partial positive. Therefore, the attraction between these partials charges will be the main force of interaction between ammonia molecules.
Other than Hydrogen bonding interactions ammonia will also experience dipole-dipole attraction and London dispersion forces.
Answer:
i think but i am not sure but according to me it mainly reacts yo non metals and i think its very reactive if my answer is wrong then comment below this question i will see it and i will get an opportunity to learn something new
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Answer: The order from weakest to strongest is:
Explanation:
Dispersion force is the weakest intermolecular force. It is a temporary attractive force that come into action when the electrons in two neighboring atoms are at the positions which results in formation of temporary dipoles.
Dipole interaction is an attractive interaction between the positive end and negative end of the polar molecule.
Hydrogen bond is a weak bond between two adjacent molecules due to an electrostatic attraction between a hydrogen atom in a molecule with an electronegative atom of an adjacent molecule.
Single covalent bond is more stronger bond than the the interaction stated above because there is sharing of an electron between two atoms.
Ionic bond is the strongest bonds in which complete transfer of electrons is present. Due to high electronegativity difference between the bonded atoms there is a high electrostatic interaction between the oppositely charged ions which makes ionic bond strongest from all the other types of the bonds.
So, the order is: