Answer:
-
-
Explanation:
Hello,
In this case, by considering the dissolution of silver bromide:
And the formation of the complex:
We obtain the balanced net ionic equation by adding the aforementioned equations:
Now, the equilibrium constant is obtained by writing the law of mass action for the non-simplified net ionic equation:
So we notice that the equilibrium constant contains the solubility constant and formation constant for the initial reactions:
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Answer:
by looking at the and researching for super long
Explanation:
Answer:
D It must be equal to 1.00
Explanation:
The refraction in the second medium must be equal to 1. The refraction index is given as the ration of the angle of incidence to the angle of refraction. This is given as a fraction. In other words:
where Θ₁ and Θ₂ are angles of incidence an refraction, and n is the refractive index.
At a critical angle, the refraction is equal to the reflection inside the medium. This results in a phenomenon called total internal reflection where light is reflected internally in the medium.
Is there supposed to be a table attached???
can’t help u
Answer:
Oxidizing agent - CrO4^2-
Reducing agent- N2O
Explanation:
Let us look at the equation closely;
CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]
The reduction half equation is;
CrO4^2- (aq) + 3e -------->Cr^3+ (aq)
Oxidation half equation is;
3N2O(g) ------>3 NO(g) +3 e
Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.