1.785714286 moles
The number of moles (n) for nitrogen is: [ n=50.0÷28.0 ] = 1.785714286 moles.
Answer:
NaCl: ionic, HF: hydrogen bond, HCl: dipole dipole , F2: dispersion force
Explanation:
complete question is:
The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion forces. Consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type.Identify each of the following ( NaCl, HF, HCl, F2) as Ionic, H Bonding, Dipole or Dispersion.
Alkanes are hydrocarbons with straight, saturated branch chains. Ring-shaped hydrocarbons are cycloalkanes. Alkenes are branch chains that are straight and have at least one double bond. Alkynes are branch chains that are straight and have at least one triple bond.
<h3>What is Hydrocarbon ?</h3>
A hydrocarbon is an organic molecule in organic chemistry that is made completely of hydrogen and carbon. Examples of group 14 hydrides include hydrocarbons. The majority of hydrocarbons are colorless and hydrophobic, and their scents are either insignificant or best characterized by those of gasoline and lighter fluid.
Other side effects from certain hydrocarbons include coma, seizures, abnormal cardiac rhythms, and liver or kidney damage. Some solvents used in paints, dry cleaning, and household cleaning solutions are examples of items that contain hazardous hydrocarbons.
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Answer:
D
Explanation:
it is neon because neon has a higher atomic number so it would have more protons and neutrons and electrons in one atom thus having more particles in one mole
Answer:
The correct statements that you must check are:
- The oxygen atom has a greater attraction for electrons than the hydrogen atom does (second statement).
- The electrons of the covalent bond are not shared equally between the hydrogen and oxygen atoms (fourth statement).
Explanation:
Electronegativity is the relative ability of an atom to pull the electrons in a covalent bond.
Hydrogen has an electronegativity of 2.20 and oxygen has 3.44. That means that oxygen attracts the electrons more strongly than hydrogen does (second statement).
As consequence, the electrons in the covalent bond H - O of water are not shared equally (fourth statement): the electron density will be higher around the O atoms.
Of course, this discards the statement telling that hydrogen atom attracts electrons much more strongly than the oxygen atom, and the statement telling that hydrogen and oxigen have same electronegativity.
Such difference in electron densities creates a dipole moment, so you discard the last statement (that the water dipole moment is equal to zero).
