If you run this reaction with 15 g of CuCl2 and 20 g NaNO3, what is the theoretical yield of NaCl?

1 answer:

7 0

The theoretical yield of a substance is the amount of the mass that is calculated from stoichiometry. The mass of sodium chloride produced is 13.03 gms.

Mass of the substance is a multiplication of the molar mass and moles.

The balanced reaction is given as:

CuCl₂ + 2NaNO₃ ⇒ 2NaCl + Cu(NO₃)₂

Moles of copper chloride are calculated as: 15 ÷ 134.45 = 0.115 moles

Moles of sodium nitrate are calculated as: 20 ÷ 84.99 = 0.2353 moles

From the reaction, 1 mole of copper chloride gives 2 moles of sodium chloride so, 0.115 moles of copper chloride will produce 0.223 moles.

Similarly, 2 moles of sodium nitrate produce 2 moles of sodium chloride so, 0.2353 moles produce 0.4706 moles.

From this, it can be concluded that copper chloride is a limiting reagent and will be used to calculate the mass of NaCl.

Mass of NaCl is calculated as: Mass = 0.223 moles × 58.44 = 13.03 gms.

Therefore, 13.03 gms is the theoretical yield of sodium chloride.

Learn more about theoretical yield here:

brainly.com/question/1419024

#SPJ1

You might be interested in

Is this chemical equation balanced?

cluponka [151]

Answer:

Yes

Explanation:

5 0

2 years ago

Read 2 more answers

Menthol is a flavoring agent extracted from peppermint oil. it contains c, h, and o. in one combustion analysis, 10.00 mg of the

marishachu [46]

Combustion reaction for menthol is as follows;
CxHyOz + O₂ ---> xCO₂ + H₂O
Mass of CO₂ formed - 28.16 mg
Therefore number of moles formed - 28.16/ 44 g/mol = 0.64 mmol
Mass of water formed - 11.53 mg
number of water moles formed - 11.53 mg/18 g/mol = 0.64 mmol
From CO₂,
1 mol of CO₂ - 1 mol of C and 2 mol of O
therefore number of C moles - 0.64 mmol
O moles - 1.28 mmol
from H₂O
1 mol of H₂O - 2 mol of H and 1 mol of O
number of H moles - 1.28 mmol
O moles - 0.64 mmol

Mass of menthol initially - 10 mg
in reactions, the masses of products are equal to the masses of reactants. The excess mass to the products formed is due to O₂ in air
Original mass of menthol - 10 mg
mass of water and CO₂ - 11.53 mg + 28.16 mg = 39.69
Difference in mass - 39.69 - 10 = 29.69 mg
This difference comes from O moles in air - 29.69 mg/ 16 g/mol = 1.8556 mmol
then O moles coming from menthol - (1.28 + 0.64) - 1.8556 = 0.064 mmol

In menthol
C moles - 0.64 mmol
H moles - 1.28 mmol
O moles - 0.064 mmol
ratios of C:H:O
C H O
0.64 1.28 0.064
x1000 x1000 x1000 to get whole numbers
640 1280 64
10 20 1
Simplest ratio of C:H:O is 10:20:1
therefore empirical formula of menthol is C₁₀H₂₀O

5 0

2 years ago

What is the answer? plz give me the right answer which you are sure of .

alisha [4.7K]

Mention four reasons why the poll ordinance failed

8 0

2 years ago

What is the formula for percent yield

Sindrei [870]

I think it is 89.3%?

3 0

2 years ago